Talk:Slater orbital: Difference between revisions
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From WP (corrected and mainly written by me).--[[User:Paul Wormer|Paul Wormer]] 04:15, 22 August 2007 (CDT) | From WP (corrected and mainly written by me).--[[User:Paul Wormer|Paul Wormer]] 04:15, 22 August 2007 (CDT) |
Latest revision as of 16:35, 14 November 2007
From WP (corrected and mainly written by me).--Paul Wormer 04:15, 22 August 2007 (CDT)
Paul, in the derivation of the normalization constant, perhaps you should explain how the normalization factor works, ie the sum of probably must add up to one, and the probability of being at any one point is ....
thus the integral equation over all space being equal to one.
David E. Volk 13:30, 9 October 2007 (CDT)
Hi David, I'm not sure I follow you completely. But as a reaction, I wrote out the normalization more explicit, and pointed out that the angular part is also normalized. As I understand you, you like to point out that the absolute square of a one-electron wave function is a probability of finding an electron at certain position? I have two objections to adding this: (1) A Slater orbital is not (yet) a wave function (is not a solution of the Sch Eq) and (2) such a remark belongs to the quantum mechanics article and does not have to be repeated over and over in quantum mechanically oriented articles. But then again, maybe I misunderstand you. Cheers, --Paul Wormer 02:39, 10 October 2007 (CDT)
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