Golden ratio

(PD) Diagram: Joel Holdsworth
demonstrating a simple method to construct a Golden Ratio rectangle

PD Image
The old townhall in Leipzig. The tower is positioned between the left (a) and right (b) sections so that $\scriptstyle {\frac {a}{b}}$ equals the golden ratio.

The golden ratio is a mathematical proportion that is important in the arts and interesting to mathematicians. In architecture and painting, some works have been proportioned to approximate the golden ratio ever since antiquity. It has been claimed that the golden ratio is found in the proportions of architectural structures ranging from the Great Pyramid of Giza, to the Parthenon, to Chartres Cathedral. In the 20th century, the golden section was applied by the French architect Le Corbusier, who used the proportion in the design of virtually all his architectural works, and in his his painting, and who wrote a series of books on the subject called The Modulor.

The ratio itself is also known as the mean and extreme ratio, the golden section, the golden mean, and the divine proportion. The earliest existing description is found in the Elements of Euclid (Book 5, definition 3): A straight line is said to have been cut in extreme and mean ratio when, as the whole line is to the greater segment, so is the greater to the less.

To be more elaborate: if there is a longer line segment $\scriptstyle a\$ and and a shorter line segment $\scriptstyle b\$, and if the ratio between $\scriptstyle a+b\$ and $\scriptstyle a\$ is equal to the ratio between the line segment $\scriptstyle a\$ and $\scriptstyle b\$, this ratio is the golden ratio. The value of the golden ratio is $\scriptstyle \Phi ={\frac {a}{b}}={\frac {1+{\sqrt {5}}}{2}}=1{,}618033988\dots$

Properties

• If ${\frac {a}{b}}={\frac {1+{\sqrt {5}}}{2}}$  it follows that ${\frac {a}{b}}={\frac {a+b}{a}}=1+{\frac {b}{a}}$

With $\Phi =1+{\frac {1}{\Phi }}$ we could derive the infinite continued fraction of the golden ratio: $\Phi =1+{\frac {1}{\Phi }}=1+{\frac {1}{1+{\frac {1}{\Phi }}}}=1+{\frac {1}{1+{\frac {1}{1+{\frac {1}{\Phi }}}}}}=\dots$

Thus

$\Phi \ =\ 1+{\frac {1}{1+{\frac {1}{1+{\frac {1}{1+\dots }}}}}}$

• $\Phi \ =\ \lim _{n\to \infty }{\frac {F(n+1)}{F(n)}}$,

where $\ F_{n}$ is the n-th term of the Fibonacci sequence.