User:Milton Beychok/Sandbox: Difference between revisions

Revision as of 11:09, 20 October 2011

${\sqrt {a^{(k+1)/(k-1)}}}=a^{(k+1)/(2k-2)}$

Revision as of 10:44, 20 October 2011 (view source) imported>Milton Beychok No edit summary ← Older edit		Revision as of 11:09, 20 October 2011 (view source) imported>Milton Beychok No edit summary Newer edit →
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	<math>\sqrt{a^{(k-1)/(k-1)}}= a^{(k-1)/(2k-2)}</math>		<math>\sqrt{a^{(k+1)/(k-1)}}= a^{(k+1)/(2k-2)}</math>