Faraday's law (electromagnetism)

In electromagnetism, Faraday's law of electromagnetic induction states that a change in magnetic flux generates an electromotive force. The law is named after the English scientist Michael Faraday.

If one rotates a conducting loop in a static magnetic field, the magnetic flux through the surface of the loop is changed. This change induces an electromotive force (voltage difference) generating an electric current in the loop. Thus, the work done in rotating the loop inside a magnetic field is converted into an electric current. In other words, Faraday's law is the theoretical basis of the dynamo and the electric generator.

Mathematical formulation

Faraday's law of electromagnetic induction relates the electromotive force (EMF) $\scriptstyle {\mathcal {E}}$ to the time derivative of the magnetic flux Φ. The law reads

${\mathcal {E}}=-k{\frac {d\Phi }{dt}}$

where k = 1 for SI units and one over c (the speed of light) for Gaussian units. The EMF is defined as

${\mathcal {E}}\equiv \oint _{C}\mathbf {E} \cdot d\mathbf {l} ,$

where the electric field E is integrated around a closed path C. The magnetic flux Φ through a surface S that has C as boundary is defined as the surface integral,

$\Phi \equiv \iint _{S}\mathbf {B} \cdot d\mathbf {S} ,$

where dS is a vector normal (perpendicular) to the infinitesimal surface element dS and dS is of length dS. The dot stands for the inner product between the magnetic induction B and dS.

In vacuum the magnetic induction B is proportional to the magnetic field H. (In SI units: B = μ₀ H with μ₀ the magnetic constant of the vacuum; in Gaussian units: B = H.)

If, in the definition of the EMF, C is a conducting loop, then under influence of the EMF a current i_ind will run through it. The minus sign in Faraday's law has the consequence that the magnetic field generated by i_ind opposes the change in Φ; this phenomenon is known as Lenz' law.

If the surface S is constant in size and direction, a change in Φ is solely due to a change in B.

The magnetic flux can be varied by changing the angle between the field and surface. For the simple case of a planar loop bordering a constant area A, and a homogeneous field B of strength B, the flux is given by

$\Phi (t)=A\mathbf {B} \cdot {\hat {\mathbf {n} }}=AB\cos \alpha (t)=\Phi (0)\cos \alpha (t),$

where $\scriptstyle {\hat {\mathbf {n} }}$ is a unit vector normal (perpendicular) to the plane S bordered by the loop. The initial condition α(0) = 0° is applied. Clearly, the flux is maximum, Φ(0), if α = 0°, i.e., if B is perpendicular to S. In the perpendicular case all of B passes through the surface. When B is parallel to surface, α = 90°, then there is no flux through the surface, Φ = 0, because B only grazes the surface.

When α(t) becomes a function of time by rotation of the loop, Faraday's law shows that an EMF is induced,

${\mathcal {E}}=k\Phi (0){\frac {d\alpha }{dt}}\sin \alpha (t).$

Magnetic flux. The flux through surface S₁ (yellow) is equal to the flux through surface S₂ (gray). Both surfaces have the contour C (red) as boundary.

The flux through two surfaces that together form a closed surface is equal because of Gauss' law. Indeed, in the figure on the right the surfaces S₁ and S₂, which have the boundary C in common, form together a closed surface. Hence Gauss' law states that

$0=-\iint _{S_{1}}\mathbf {B} \cdot d\mathbf {S} +\iint _{S_{2}}\mathbf {B} \cdot d\mathbf {S} ,$

where the minus sign of the first term is due to the fact that the flux is into the volume enveloped by the two surfaces. It follows that

$\Phi =\iint _{S_{1}}\mathbf {B} \cdot d\mathbf {S} =\iint _{S_{2}}\mathbf {B} \cdot d\mathbf {S} ,$

and that the magnetic flux Φ can be computed with respect to any surface that has C as boundary.

Connection to Maxwell's equation

Application of Stokes' theorem gives

$\oint _{C}\mathbf {E} \cdot d\mathbf {l} =\iint _{S}{\big (}{\boldsymbol {\nabla }}\times \mathbf {E} {\big )}\cdot d\mathbf {S} ,$

where S is a surface that has C as boundary. From rewriting Faraday's law as follows,

$\iint _{S}{\big (}{\boldsymbol {\nabla }}\times \mathbf {E} {\big )}\cdot d\mathbf {S} =-k{\frac {d}{dt}}\iint _{S}\mathbf {B} \cdot d\mathbf {S} =-k\iint _{S}{\frac {\partial \mathbf {B} }{\partial t}}\cdot d\mathbf {S}$

and the fact that S is arbitrary, we may conclude

${\boldsymbol {\nabla }}\times \mathbf {E} =-k{\frac {\partial \mathbf {B} }{\partial t}},$

which is one of Maxwell's equations. Recall that k = 1 for SI units and k = 1/c for Gaussian units.

Connection to Lorentz force

CC Image
Conducting bar moves to the right on conducting rails in homogeneous field B. Surface grows with v. Lorentz force is downward and gives an electric current i_ind in clockwise direction around the closed circuit.

It is instructive to derive Faraday's law from the Lorentz force for a special case. To that end an experimental setup is depicted in the figure on the right. A conducting bar of length a moves in positive x direction over two parallel pairs of conducting rails. The speed v of the bar is constant. The whole setup is placed in a homogeneous magnetic field B = μ₀ H (we are using SI units) that points toward the reader, i.e., in positive z-direction. Homogeneity means that everywhere in the plane of drawing a magnetic field B of the same strength points toward the reader (parallel to the z-axis).

The magnetic field is constant, but the surface S increases linearly in time

$S=xa\Longrightarrow {\frac {dS}{dt}}={\frac {dx}{dt}}a\equiv va.$

The vector B points in positive z-direction and so does the normal to S,

${\begin{aligned}{\frac {d}{dt}}\iint _{S}\mathbf {B} \cdot d\mathbf {S} &={\frac {d}{dt}}\iint _{S}BdS\\&=B{\frac {d}{dt}}\iint _{S}dS=B{\frac {dS}{dt}}=Bva.\end{aligned}}$

The time-dependence of the growing flux is solely due to the time-dependence of the growth of the surface. The time derivative of the magnetic flux in the figure is positive and equal to

${\frac {d\Phi }{dt}}=Bva.\qquad \qquad \qquad \qquad \qquad \qquad \qquad (1)$

The Lorentz force (in SI units) is the cross product,

$\mathbf {F} _{\mathrm {Lor} }=\mathbf {v} \times \mathbf {B} =-\mathbf {e} _{y}vB,$

where e_y is a unit vector along the y-axis. In order to obtain the electromotive force (EMF) one must integrate the inner product of electric force with path, F_Lor⋅dl, counter-clockwise around the circuit consisting of: the moving bar, the two pairs of unmoving rails and the unmoving conductor containing the ampmeter. The integration is counter-clockwise because of the right-hand screw rule applied to the direction of B. Except for the moving bar, where the force is constant and non-zero, there is no force in the circuit. The constant force acts over the length a of the moving bar and gives an EMF equal to force times path length,

${\mathcal {E}}=\int _{0}^{a}\mathbf {F} _{\mathrm {Lor} }\cdot d\mathbf {l} =-vBa\qquad \qquad \qquad \qquad (2).$

From equations (1) and (2) follows

${\mathcal {E}}=-{\frac {d\Phi }{dt}},$

which indeed is Faraday's law of magnetic induction.

The EMF gives a current i_ind in the direction of the Lorentz force, i.e., in a clockwise direction in the plane of drawing (the x-y plane). By Biot-Savart's law a current gives a circular magnetic field. The current i_ind has a tangent vector in the x-y plane that is in negative z-direction. Hence B_ind opposes B, in accordance with Lenz' law.