Square root of two: Difference between revisions
imported>Sébastien Moulin m (→In Right Triangles: correcting TeX syntax) |
imported>Graham Nelson (→Proof of Irrationality: grammar) |
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There exists a simple proof by contradiction showing that <math>\sqrt{2}</math> is irrational: | There exists a simple proof by contradiction showing that <math>\sqrt{2}</math> is irrational: | ||
Assume that there | Assume that there exist two numbers, <math>x, y \in \mathbb{N}</math>, such that <math>\frac{x}{y} = \sqrt{2}</math> and <math>x</math> and <math>y</math> represent the smallest such [[integer|integers]] (i.e., they are [[mutually prime]]). | ||
Therefore, <math>\frac{x^2}{y^2} = 2</math> and <math>x^2 = 2 \times y^2</math>, | Therefore, <math>\frac{x^2}{y^2} = 2</math> and <math>x^2 = 2 \times y^2</math>, |
Revision as of 10:35, 15 April 2007
The square root of two, denoted , is the positive number whose square equals 2. It is approximately 1.4142135623730950488016887242097. It provides a typical example of an irrational number.
In Right Triangles
The square root of two plays an important role in right triangles in that a unit right triangle (where both legs are equal to 1), has a hypotenuse of . Thus, .
Proof of Irrationality
There exists a simple proof by contradiction showing that is irrational:
Assume that there exist two numbers, , such that and and represent the smallest such integers (i.e., they are mutually prime).
Therefore, and ,
Thus, represents an even number
If we take the integer, , such that , and insert it back into our previous equation, we find that
Through simplification, we find that , and then that, ,
Since is an integer, must also be even. However, if and are both even, they share a common factor of 2, making them not mutually prime. And that is a contradiction.